COSMOS AND UNIVERSES: The Final Theory of the Cosmos and the Universes by Balslev J

Author:Balslev, J. [Balslev, J.]
Language: eng
Format: epub
Published: 2020-05-03T16:00:00+00:00

M NS = 3.2 M ⊙ = 3.2 · 1.99×1030 kg = 6.37×1030 kg,

where, M ⊙ = 1.99×1030 kg, [120] is the solar mass. Since each neutron releases the energy E n = 1.49×10‒10 J and the mass of the neutron is m n = 1.67×10‒27 kg, [114] the total energy content of a neutron star must be equal to:

E (NS) = 6.37×1030 /1.67×10‒27 · 1.49×10‒10 J = 5.7×1047 J ≈ 3.6×1060 MeV,

as 1 J ≈ 6.242×1012 MeV. Some researchers set the density of the neutron star at the time of the explosion to at least 1.0×1018 kg/m3 . [86] So a cubic meter of such a neutron star must at least release the energy:

Download

Copyright Disclaimer:
This site does not store any files on its server. We only index and link to content provided by other sites. Please contact the content providers to delete copyright contents if any and email us, we'll remove relevant links or contents immediately.